find the sum of the first 5 terms 4 12 36 108 ​

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find the sum of the first 5 terms 4 12 36 108 ​

Answer:

To find the sum of the first 5 terms of the geometric sequence 4, 12, 36, 108, we can use the formula for the sum of a geometric series:

S = a * (1 - r^n) / (1 - r)

Where:

S is the sum of the series,

a is the first term,

r is the common ratio,

and n is the number of terms.

In this case:

a = 4 (the first term)

r = 3 (the common ratio, as each term is obtained by multiplying the previous term by 3)

n = 5 (the number of terms)

Let's calculate the sum:

S = 4 * (1 - 3^5) / (1 - 3)

= 4 * (1 - 243) / (-2)

= 4 * (-242) / (-2)

= 484

Therefore, the sum of the first 5 terms of the geometric sequence 4, 12, 36, 108 is 484.

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