(3×4÷2^2+3)×(6÷3×5−5×2+1)−5
Answer:
To solve the expression (3×4÷2^2+3)×(6÷3×5−5×2+1)−5, we can follow the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).
First, let's simplify the expressions inside the parentheses:
(3×4÷2^2+3) becomes (3×4÷4+3) which further simplifies to (12÷4+3) resulting in (3+3) which equals 6.
Next, let's simplify the second set of parentheses:
(6÷3×5−5×2+1) becomes (2×5−10+1) which simplifies to (10−10+1) resulting in 1.
Now, we can substitute the simplified expressions back into the original equation:
6×1−5 becomes 6−5 resulting in 1.
Therefore, the value of the expression (3×4÷2^2+3)×(6÷3×5−5×2+1)−5 is 1.